Integrand size = 16, antiderivative size = 154 \[ \int \frac {\left (a+b \arctan \left (c x^3\right )\right )^2}{x} \, dx=\frac {2}{3} \left (a+b \arctan \left (c x^3\right )\right )^2 \text {arctanh}\left (1-\frac {2}{1+i c x^3}\right )-\frac {1}{3} i b \left (a+b \arctan \left (c x^3\right )\right ) \operatorname {PolyLog}\left (2,1-\frac {2}{1+i c x^3}\right )+\frac {1}{3} i b \left (a+b \arctan \left (c x^3\right )\right ) \operatorname {PolyLog}\left (2,-1+\frac {2}{1+i c x^3}\right )-\frac {1}{6} b^2 \operatorname {PolyLog}\left (3,1-\frac {2}{1+i c x^3}\right )+\frac {1}{6} b^2 \operatorname {PolyLog}\left (3,-1+\frac {2}{1+i c x^3}\right ) \]
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Time = 0.21 (sec) , antiderivative size = 154, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {4944, 4942, 5108, 5004, 5114, 6745} \[ \int \frac {\left (a+b \arctan \left (c x^3\right )\right )^2}{x} \, dx=\frac {2}{3} \text {arctanh}\left (1-\frac {2}{1+i c x^3}\right ) \left (a+b \arctan \left (c x^3\right )\right )^2-\frac {1}{3} i b \operatorname {PolyLog}\left (2,1-\frac {2}{i c x^3+1}\right ) \left (a+b \arctan \left (c x^3\right )\right )+\frac {1}{3} i b \operatorname {PolyLog}\left (2,\frac {2}{i c x^3+1}-1\right ) \left (a+b \arctan \left (c x^3\right )\right )-\frac {1}{6} b^2 \operatorname {PolyLog}\left (3,1-\frac {2}{i c x^3+1}\right )+\frac {1}{6} b^2 \operatorname {PolyLog}\left (3,\frac {2}{i c x^3+1}-1\right ) \]
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Rule 4942
Rule 4944
Rule 5004
Rule 5108
Rule 5114
Rule 6745
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \text {Subst}\left (\int \frac {(a+b \arctan (c x))^2}{x} \, dx,x,x^3\right ) \\ & = \frac {2}{3} \left (a+b \arctan \left (c x^3\right )\right )^2 \text {arctanh}\left (1-\frac {2}{1+i c x^3}\right )-\frac {1}{3} (4 b c) \text {Subst}\left (\int \frac {(a+b \arctan (c x)) \text {arctanh}\left (1-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx,x,x^3\right ) \\ & = \frac {2}{3} \left (a+b \arctan \left (c x^3\right )\right )^2 \text {arctanh}\left (1-\frac {2}{1+i c x^3}\right )+\frac {1}{3} (2 b c) \text {Subst}\left (\int \frac {(a+b \arctan (c x)) \log \left (\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx,x,x^3\right )-\frac {1}{3} (2 b c) \text {Subst}\left (\int \frac {(a+b \arctan (c x)) \log \left (2-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx,x,x^3\right ) \\ & = \frac {2}{3} \left (a+b \arctan \left (c x^3\right )\right )^2 \text {arctanh}\left (1-\frac {2}{1+i c x^3}\right )-\frac {1}{3} i b \left (a+b \arctan \left (c x^3\right )\right ) \operatorname {PolyLog}\left (2,1-\frac {2}{1+i c x^3}\right )+\frac {1}{3} i b \left (a+b \arctan \left (c x^3\right )\right ) \operatorname {PolyLog}\left (2,-1+\frac {2}{1+i c x^3}\right )+\frac {1}{3} \left (i b^2 c\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}\left (2,1-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx,x,x^3\right )-\frac {1}{3} \left (i b^2 c\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}\left (2,-1+\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx,x,x^3\right ) \\ & = \frac {2}{3} \left (a+b \arctan \left (c x^3\right )\right )^2 \text {arctanh}\left (1-\frac {2}{1+i c x^3}\right )-\frac {1}{3} i b \left (a+b \arctan \left (c x^3\right )\right ) \operatorname {PolyLog}\left (2,1-\frac {2}{1+i c x^3}\right )+\frac {1}{3} i b \left (a+b \arctan \left (c x^3\right )\right ) \operatorname {PolyLog}\left (2,-1+\frac {2}{1+i c x^3}\right )-\frac {1}{6} b^2 \operatorname {PolyLog}\left (3,1-\frac {2}{1+i c x^3}\right )+\frac {1}{6} b^2 \operatorname {PolyLog}\left (3,-1+\frac {2}{1+i c x^3}\right ) \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 201, normalized size of antiderivative = 1.31 \[ \int \frac {\left (a+b \arctan \left (c x^3\right )\right )^2}{x} \, dx=a^2 \log (x)+\frac {1}{3} i a b \left (\operatorname {PolyLog}\left (2,-i c x^3\right )-\operatorname {PolyLog}\left (2,i c x^3\right )\right )+\frac {1}{72} b^2 \left (-i \pi ^3+16 i \arctan \left (c x^3\right )^3+24 \arctan \left (c x^3\right )^2 \log \left (1-e^{-2 i \arctan \left (c x^3\right )}\right )-24 \arctan \left (c x^3\right )^2 \log \left (1+e^{2 i \arctan \left (c x^3\right )}\right )+24 i \arctan \left (c x^3\right ) \operatorname {PolyLog}\left (2,e^{-2 i \arctan \left (c x^3\right )}\right )+24 i \arctan \left (c x^3\right ) \operatorname {PolyLog}\left (2,-e^{2 i \arctan \left (c x^3\right )}\right )+12 \operatorname {PolyLog}\left (3,e^{-2 i \arctan \left (c x^3\right )}\right )-12 \operatorname {PolyLog}\left (3,-e^{2 i \arctan \left (c x^3\right )}\right )\right ) \]
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\[\int \frac {{\left (a +b \arctan \left (c \,x^{3}\right )\right )}^{2}}{x}d x\]
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\[ \int \frac {\left (a+b \arctan \left (c x^3\right )\right )^2}{x} \, dx=\int { \frac {{\left (b \arctan \left (c x^{3}\right ) + a\right )}^{2}}{x} \,d x } \]
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\[ \int \frac {\left (a+b \arctan \left (c x^3\right )\right )^2}{x} \, dx=\int \frac {\left (a + b \operatorname {atan}{\left (c x^{3} \right )}\right )^{2}}{x}\, dx \]
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\[ \int \frac {\left (a+b \arctan \left (c x^3\right )\right )^2}{x} \, dx=\int { \frac {{\left (b \arctan \left (c x^{3}\right ) + a\right )}^{2}}{x} \,d x } \]
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\[ \int \frac {\left (a+b \arctan \left (c x^3\right )\right )^2}{x} \, dx=\int { \frac {{\left (b \arctan \left (c x^{3}\right ) + a\right )}^{2}}{x} \,d x } \]
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Timed out. \[ \int \frac {\left (a+b \arctan \left (c x^3\right )\right )^2}{x} \, dx=\int \frac {{\left (a+b\,\mathrm {atan}\left (c\,x^3\right )\right )}^2}{x} \,d x \]
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